Answered

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Given the function h(x) = x^2 + 10x + 32, determine the average rate of change
of the function over the interval 3 < x < 11.

Sagot :

Answer:  24

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Explanation:

Plug in x = 3 to get

h(x) = x^2 + 10x + 32

h(3) = 3^2 + 10*3 + 32

h(3) = 71

Repeat for x = 11

h(x) = x^2 + 10x + 32

h(11) = 11^2 + 10*11 + 32

h(11) = 263

Now use the average rate of change formula

m = average rate of change

m = ( h(b) - h(a) )/(b - a)

m = ( h(11) - h(3) )/(11 - 3)

m = (263 - 71)/(11 - 3)

m = 192/8

m = 24

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