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Sagot :
Following are the steps of the polynomial-time algorithm:
- Split the routes according to their categorization
- Assuming that mid = di of the middle road, low = road with the least di, and high = road with the highest di, we may do a binary search on the sorted list.
- All shops must be approachable only using these roads for every road, from low to mid.
- Check if all shops can be reached from[tex]\bold{ low \ to\ mid+1}[/tex] using only these roads.
- There is a solution if every shop can be reached by road only up to [tex]\bold{mid+1}[/tex], but not up to mid.
- You can [tex]\bold{set \ low = mid+1}[/tex] if all businesses aren't accessible using both [tex]\bold{mid\ and\ mid+1}[/tex] roads.
- If every shop could be reached using both mid and mid+1, then set high to mid-1.
- With these layouts of businesses and roads, no response can be given because [tex]\bold{ low > high}[/tex]
- You can do this by [tex]\bold{set\ mid = \frac{(low + high)}{2}}[/tex]
- The new low, mid, and high numbers are used in step (a).
In a minimum amount of time, this algorithm will determine the best strategy to supply all shops.
Learn more:
polynomial-time algorithm: brainly.com/question/20261998
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