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Solving the quadratic equation 3x^2+12x=-14 by quadratic formula

Sagot :

sqdancefan

9514 1404 393

Answer:

  x = -2 ±i(√6)/3

Step-by-step explanation:

The formula for the solution of ax²+bx+c=0 is ...

  [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

When your equation is written in standard form, it is ...

  3x² +12x +14 = 0

so the values needed in the formula are a=3, b=12, c=14.

  [tex]x=\dfrac{-12\pm\sqrt{12^2-4(3)(14)}}{2(3)}=\dfrac{-12\pm\sqrt{-24}}{6}=\dfrac{-12\pm2i\sqrt{6}}{6}\\\\\boxed{x=-2\pm\dfrac{\sqrt{6}}{3}i}[/tex]

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