kennedeiholloway1
Answered

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please help! x^3 +y^3=9

Please Help X3 Y39 class=

Sagot :

Trancescient

Step-by-step explanation:

Taking the derivative of both sides with respect to x, we get

[tex]\dfrac{d}{dx}(x^3 + y^3) = \dfrac{d}{dx}(3)[/tex]

[tex]\Rightarrow 3x^2 + 3y^2\dfrac{dy}{dx} = 0[/tex]

Solving for [tex]\frac{dy}{dx}[/tex], we get

[tex]\dfrac{dy}{dx} = -\dfrac{3x^2}{3y^2} = -\dfrac{x^2}{y^2}[/tex]

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