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Sagot :
[tex]\\ \sf\longmapsto \left[{3a+b\atop a-b}\:\:\:{3c-d\atop a+b+d}\right]=\left[{3\atop 5}\:\:\;{6\atop 2d-1}\right][/tex]
Now constructing equations
[tex]\\ \sf\longmapsto 3a+b=3\dots(1)[/tex]
[tex]\\ \sf\longmapsto a-b=5\dots(2)[/tex]
[tex]\\ \sf\longmapsto 3c-d=6\dots(3)[/tex]
[tex]\\ \sf\longmapsto a+b+d=2d-1\dots(4)[/tex]
Adding eq(1) and (2)
[tex]\\ \sf\longmapsto 4a=8[/tex]
[tex]\\ \sf\longmapsto a=\dfrac{8}{4}[/tex]
[tex]\\ \bf\longmapsto a=2[/tex]
Put the value in eq(2)
[tex]\\ \sf\longmapsto a-b=5[/tex]
[tex]\\ \sf\longmapsto b=a-5[/tex]
[tex]\\ \sf\longmapsto b=2-5[/tex]
[tex]\\ \bf\longmapsto b=-3[/tex]
put the values in eq(4)
[tex]\\ \sf\longmapsto a+b+d=2d-1[/tex]
[tex]\\ \sf\longmapsto 2+(-3)+d=2d-1[/tex]
[tex]\\ \sf\longmapsto d-1=2d-1[/tex]
[tex]\\ \sf\longmapsto d-2d=-1+1[/tex]
[tex]\\ \sf\longmapsto -d=0[/tex]
[tex]\\ \bf\longmapsto d=0[/tex]
Put the value in eq(3)
[tex]\\ \sf\longmapsto 3c-d=6[/tex]
[tex]\\ \sf\longmapsto 3c-0=6[/tex]
[tex]\\ \sf\longmapsto 3c=6+0[/tex]
[tex]\\ \sf\longmapsto 3c=6[/tex]
[tex]\\ \sf\longmapsto c=\dfrac{6}{3}[/tex]
[tex]\\ \sf\longmapsto c=2[/tex]
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