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Sagot :
Answer:
see explanation
Step-by-step explanation:
The sum to n terms of a geometric series is
[tex]S_{n}[/tex] = [tex]\frac{a_{1}(r^{n}-1) }{r-1}[/tex]
where a₁ is the first term and r the common ratio
Given a₁ = 3 and r = - 2 , then
3 × - 2 = - 6
- 6 × -2 = 12
12 × - 2 = - 24
- 24 × - 2 = 48
48 × - 2 = - 96
- 96 × - 2 = 192
The positive terms are in a geometric progression
3, 12, 48, 192, ....
with a₁ = 3 and r = 12 ÷ 3 = 48 ÷ 12 = 4 , then
S₈ = [tex]\frac{3(4^{8}-1) }{4-1}[/tex] = [tex]\frac{3(65536-1)}{3}[/tex] = 65536 - 1 = 65535
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