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Sagot :
The probability that he receives an invitation to work in a bank given that he defends his diploma excellently is [tex]\mathbf{0. \overline 6}[/tex]
The reason for the above probability value is as follows;
The known parameters are;
The probability that a graduate of the Faculty of Finance will defend the diploma excellently, P(A) = 0.6
The probability that he will defend perfectly and receive an invitation to work at a bank, P(A∩B) = 0.4
The unknown parameter is;
The probability that the student will receive an invitation from the bank given that the student defend the diploma excellent, [tex]\mathbf {P(B \ | \ A)}[/tex]
The process;
[tex]\mathbf{ P(B \ | \ A)}[/tex] is found using the conditional probability formula as follows;
[tex]\mathbf {P(B \ | \ A) = \dfrac{P(A \cap B) }{P(A)}}[/tex]
Plugging in the values, we get;
[tex]P(B \ | \ A) = \dfrac{0.4 }{0.6} = \dfrac{2}{3} = 0. \overline 6[/tex]
The probability that the student will receive an invitation from the bank given that the student defend the diploma excellent, [tex]P(B \ | \ A)[/tex] = [tex]\mathbf {0. \overline 6}[/tex]
Learn more about conditional probability here;
https://brainly.com/question/10567654
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