Answered

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Convert 9x2 + 4y2 – 54x – 8y – 59 = 0 into standard form.

Sagot :

kayla71807

Answer:

[tex]\frac{(x-3)^2}{4^2} +\frac{(y-1)^2}{6^2} =1[/tex]

Step-by-step explanation:

[tex]9x^{2}+4y^{2} -54x-8y-59=0[/tex]

[tex]9x^{2}-54x+4y^{2} -8y=59[/tex]

Factor 9 and 4 out

[tex]9(x^2-6x)+4(y^2-2y)=59[/tex]

Complete the square, don't forget to add the 2 extra numbers

[tex]9(x-3)^2+4(y-1)^2=59+81+4[/tex]

[tex]9(x-3)^2+4(y-1)^2=144\\[/tex]

Divide everything by 144

[tex]\frac{(x-3)^2}{16} +\frac{(y-1)^2}{36} =1[/tex]

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