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Find the value of x to the nearest tenth.

Find The Value Of X To The Nearest Tenth class=

Sagot :

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Answer:

x = 7.8

Step-by-step explanation:

a^2 + b^2 = c^2

4^2 + 2^2 = c^2

16 + 4 = c^2

c^2 = 20

c = 4.5

a^2 + b^2 = c^2

a^2 + 4.5^2 = 9^2

a^2 + 20.25 = 81

a^2 = 81 - 20.25

a^2 = 60.75

a = 7.8

Answer:

Step-by-step explanation:

Using Pythagoreus Theorem

In the smaller rectangle

2²+4² = h²

20 = h²

h = √20

h = 2√5

Therefore two sides of the rectangle will 2√5

No using pythagoreus theorem in the bigger triangle

x² + (2√5)² = 9²

x² = 9² - (2√5)²

x² = 81 - 20

x = √61

x = 7.8102496759

When rounded off to nearest tenth the hundreth digit is in 0-5 range

x = 7.81

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