aadityanayyar10
Answered

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13. Find the smallest number which when divided by 21,28,36 and 44 leaves a
remainder of 3 in each case?

Sagot :

jcherry99

Answer:

2775

Step-by-step explanation:

Well of course since the problem is not restricted, the smallest number is 3. I'm almost sure that's not what you mean. The next smallest number is 2775. I found that using a  programing language. I'm sure as well that does not satisfy the question, either.

I think you are intended to do this by finding the lowest common multiple and adding 3.

21: 3 * 7

28: 2 * 2 * 7

36: 2 * 2 * 3 * 3

44: 2 * 2 * 11

LCM = 2 * 2 * 3 * 3 * 7 * 11 = 2772

Now add 3 and the number you want is 2775

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