maliman0412
Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Please Help!!!!!!!
Janet is going to draw a marble from the bag shown below, replace it, and then draw another marble. What is the
probability that Janet will get a blue or yellow marble on the first draw and a pink on the second draw?
(3 green, 4 yellow, 5 blue, 8 pink)
7/50
9/50
17/40

Sagot :

cwayneu

(Answer:

P(Bl or Yl) = 45%

(Pk on 2nd draw) = 18%

Step-by-step explanation:

There are a total of 20 marbles (3 + 4 + 5 + 8) in the bag. Since each marble is replaced once drawn, there is no change in the total count from one draw to another (unconditional probability).

So

P(Bl or Yl) = (5 + 4)/20 = 9/20 = .45 = 45%

Then

P(Pk on 2nd draw) = P(1st draw) * P(2nd draw)

     = 9/20 * 8/20 = 72/400 = 9/50 = .18 = 18%

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.