moneylovers
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Part A: Estimate the IQR for the males' data. (2 points)

Part B: Estimate the difference between the median values of each data set. (2 points)

Part C: Describe the distribution of the data and if the mean or median would be a better measure of center for each. (4 points)

Part D: Provide a possible reason for the outlier in the data set. (2 points)

Part A Estimate The IQR For The Males Data 2 Points Part B Estimate The Difference Between The Median Values Of Each Data Set 2 Points Part C Describe The Distr class=

Sagot :

Part A: 23

Part B: 13

Part C: Median for the males

Mean for the females

Part D: The day the movie premiered

Process to arrive at the above answers

The likely missing part of the question; The Box Plots are to compare The Number of Males and The Number of Females attending the latest superhero movie every day in a given month

The known parameters

The 5 number summary in a are;

[tex]\begin{array}{lcc}\mathbf{Summary}&\mathbf{Males}&\mathbf{Females}\\\\Minimum &0&0\\First \ Quartile, \ Q_1&2&5\\Second \ Quartile, \ median, Q_2&20&7\\Third \ Quartile, Q_3&25&10\\Maximum &50&18\\Outlier&&46\end{array}[/tex]

Part A: The Inter Quartile Range, IQR = Q₃ - Q₁

For the males, we have, IQR = 25 - 2 = 23

Part B: The difference between the median values for the males and females is given as follows;

Difference between median = Q₂ Males - Q₂ Females

∴ Difference between median = 20 - 7 = 13

The difference between the median values for the males and females = 13

Part C:

The distribution of the data for the males is skewed left, with almost all the data in the first half

The better measure of center for the skewed data is the median, given

that three quarter of the data have values that are less than half of the

range of values in the data set, and that the median is close to the third

quartile, the mean will be located further towards the minimum value of

the data than the median

The distribution of the data for the females consists of the interquartile

range located approximately in the middle between the max and the min

values with the median being close to the first quartile, therefore, the

mean will be a better measure of center as it will be located further from

the first quartile and closer midway in the IQR

Part D;

The possible reason for the outlier in the data set may be due to the first day the latest super hero movie is premiered

Learn more about box plots here;

https://brainly.com/question/16171899

https://brainly.com/question/20164121

https://brainly.com/question/17248599

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