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Sagot :
The probability where exactly three of the faculty have tenure is 0.3916.
The computation of the probability where exactly three of the faculty have tenure is given below:
Since there are 6 faculty from 15 should be chosen so it should be [tex]^{15}C_6[/tex]
Now there are 3 faculty from 7 should be chosen so it should be [tex]^{7}C_3[/tex]
Now the probability is
[tex]= \frac{^7C_3 \times ^8C_3}{^{15}C_6}[/tex]
= 0.3916
Therefore we can conclude that the probability where exactly three of the faculty have tenure is 0.3916.
Learn more about the probability here: brainly.com/question/11234923
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