Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Johnny was able to drive an average of 31 miles per hour faster in his car after the traffic cleared. He drove 16 miles in traffic before it cleared and then drove another 47 miles. If the total trip took 2 hours, then what was his average speed in traffic?

Sagot :

9514 1404 393

Answer:

  16 mi/h

Step-by-step explanation:

The time for a given leg of the trip is the distance divided by the speed. If t is the speed in traffic, the total trip time is ...

  16/t +47/(t+31) = 2

Multiplying by t(t+31), we get ...

  16(t +31) +47t = 2(t)(t+31)

  2t^2 -t -496 = 0 . . . . put in standard form

  (2t +31)(t -16) = 0 . . . . factor

The positive solution is t = 16.

Johhny's average speed in traffic was 16 mph.

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.