shaanrmehta
Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Appreciate answers and any help!


Logan wants to know how many skateboards have defective parts. He inspects 20,000 skateboards and keeps track of the number of defects per board. Use his probability distribution table to find the expected value for defects on a skateboard.

Appreciate Answers And Any HelpLogan Wants To Know How Many Skateboards Have Defective Parts He Inspects 20000 Skateboards And Keeps Track Of The Number Of Defe class=

Sagot :

To find the expected value of the distribution, we multiply each outcome by it's probability. Doing this, we get that the expected value of defects on a skateboard is of [tex]\frac{4}{25}[/tex].

Outcomes and probabilities:

0 defects, 9/10 probability

1 defect, 1/20 probability

2 defects, 1/25 probability

3 defects, 1/100 probability.

Expected value:

[tex]E(X) = 0\frac{9}{10} + \frac{1}{20} + 2\frac{1}{25} + 3\frac{1}{100} = \frac{1}{20} + \frac{2}{25} + \frac{3}{100} = \frac{5 + 8 + 3}{100} = \frac{16}{100}[/tex]

Dividing both numerator and denominator by 4:

[tex]\frac{4}{25}[/tex]

Thus, the expected value of defects on a skateboard is of [tex]\frac{4}{25}[/tex].

A similar problem is given at: https://brainly.com/question/23156292.

We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.