shaanrmehta
Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Appreciate answers and any help!


Logan wants to know how many skateboards have defective parts. He inspects 20,000 skateboards and keeps track of the number of defects per board. Use his probability distribution table to find the expected value for defects on a skateboard.

Appreciate Answers And Any HelpLogan Wants To Know How Many Skateboards Have Defective Parts He Inspects 20000 Skateboards And Keeps Track Of The Number Of Defe class=

Sagot :

To find the expected value of the distribution, we multiply each outcome by it's probability. Doing this, we get that the expected value of defects on a skateboard is of [tex]\frac{4}{25}[/tex].

Outcomes and probabilities:

0 defects, 9/10 probability

1 defect, 1/20 probability

2 defects, 1/25 probability

3 defects, 1/100 probability.

Expected value:

[tex]E(X) = 0\frac{9}{10} + \frac{1}{20} + 2\frac{1}{25} + 3\frac{1}{100} = \frac{1}{20} + \frac{2}{25} + \frac{3}{100} = \frac{5 + 8 + 3}{100} = \frac{16}{100}[/tex]

Dividing both numerator and denominator by 4:

[tex]\frac{4}{25}[/tex]

Thus, the expected value of defects on a skateboard is of [tex]\frac{4}{25}[/tex].

A similar problem is given at: https://brainly.com/question/23156292.

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.