shaanrmehta
Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Appreciate answers and any help!


Logan wants to know how many skateboards have defective parts. He inspects 20,000 skateboards and keeps track of the number of defects per board. Use his probability distribution table to find the expected value for defects on a skateboard.

Appreciate Answers And Any HelpLogan Wants To Know How Many Skateboards Have Defective Parts He Inspects 20000 Skateboards And Keeps Track Of The Number Of Defe class=

Sagot :

To find the expected value of the distribution, we multiply each outcome by it's probability. Doing this, we get that the expected value of defects on a skateboard is of [tex]\frac{4}{25}[/tex].

Outcomes and probabilities:

0 defects, 9/10 probability

1 defect, 1/20 probability

2 defects, 1/25 probability

3 defects, 1/100 probability.

Expected value:

[tex]E(X) = 0\frac{9}{10} + \frac{1}{20} + 2\frac{1}{25} + 3\frac{1}{100} = \frac{1}{20} + \frac{2}{25} + \frac{3}{100} = \frac{5 + 8 + 3}{100} = \frac{16}{100}[/tex]

Dividing both numerator and denominator by 4:

[tex]\frac{4}{25}[/tex]

Thus, the expected value of defects on a skateboard is of [tex]\frac{4}{25}[/tex].

A similar problem is given at: https://brainly.com/question/23156292.

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.