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A father's age now is three times the age that his son was 4 years ago. In 12 years, the father will be twice as old as his son. find their ages now.

Sagot :

Answer:

In this problem, we can assign X to the son’s age and Y to the father’s.

We know that a father is 3 times as old as his son.

Therefore, we can create the equation 3X=Y.

We must now create a second equation from the remaining information, being “In 12 years he will be twice as old as his son”. We know we can add 12 years, along with including 2X in the equation.

The equation that we can gather from this second piece of information will be Y=2X+12. This is because the father’s age, in 12 year’s time, will be twice that of the child.

Now we have our two equations:

Y=3X

Y=2X+12

Because both equations are set equal to the age of the father, we can use the substitution method to solve in terms of the son’s age, as follows:

3X = 2X+12

Now we subtract 2X from each side to isolate the variable:

X=12

The son’s age is therefore 12 years old. Should we plug that age back into our first equation, we get Y=3(12) or Y=36.

The father’s present age is 36, while the son’s present age is 12.

The current age of the father is 12, while the age of the son is 0.

How to form an equation?

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

In other words, an equation is a set of variables that are constrained through a situation or case.

Let say,

X = age of sun

Y = age of father

Given that

A father's age now is three times the age that his son was 4 years ago

So,

Y = 3(X -4)

Y = 3X - 12

And  In 12 years, the father will be twice as old as his son

Y + 12 = 2( X + 12 )

Y = 2X - 12

From booth equation

X = 0 and Y = -12 which is not practical so Y =12

For more about equation

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