Answered

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tanx-sinx÷tanx-sinx=1-cosx ÷sinx

Sagot :

johnaldredomandam

Answer:

Given:

(sin5x−sinx)(cos4x−cos6x)

(cosx−cos3x)(sin8x+sin2x)

Use the formula:

sina+sinb=2sin(

2

a+b

)cos(

2

a−b

)

sina−sinb=2cos(

2

a+b

)sin(

2

a−b

)

cosa−cosb=−2sin(

2

a+b

)sin(

2

a−b

)

(sin5x−sinx)(cos4x−cos6x)

(cosx−cos3x)(sin8x+sin2x)

=

(2cos

2

6x

sin

2

4x

)(−2sin

2

10x

sin

2

−2x

)

(−2sin

2

4x

sin

2

−2x

)(2sin

2

10x

cos

2

6x

)

=

(2cos3xsin2x)(2sin5xsinx)

(2sin2xsinx)(2sin5xcos3x)

=1

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