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What is the product of all values of b that satisfy (b-2)(b-8) +4= 0 ?
A) 10
B) 12
C) 16
D) 20


Sagot :

Answer:

D

Step-by-step explanation:

(b-2)(b-8)+4=0

b^2-10b+16+4=0

b^2-10b+20=0

Product of roots is given by c/a=20. So the answer is 20