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Sagot :

We can solve it through proportionality or ratios

  • 2 lamps required to create 4signals

Let lamps required to create 60signals be x

Now

[tex]\\ \sf\longmapsto 2:4=x:60[/tex]

[tex]\\ \sf\longmapsto \dfrac{2}{4}=\dfrac{x}{60}[/tex]

[tex]\\ \sf\longmapsto 4x=60(2)[/tex]

[tex]\\ \sf\longmapsto 4x=120[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{120}{4}[/tex]

[tex]\\ \sf\longmapsto x=30[/tex]

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