Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Step-by-step explanation:
[tex]a {}^{3} + b {}^{3} [/tex]
Notice how that for both a and b are raised to an odd power. This means we can factor this by a binomial raised to an odd power.
Let divide this by
[tex]a + b[/tex]
Since that is also a odd power.
[tex]( {a}^{3} + {b}^{3} ) \div (a + b)[/tex]
We get
a quotient of
[tex]( {a}^{2} - ab + {b}^{2} )[/tex]
So our factors are
[tex](a + b)( {a}^{2} - ab + {b}^{2} )[/tex]
Answer:
[tex](a+b)(a^{2} -ab+b^{2} )[/tex]
Step-by-step explanation:
[tex]\textbf{We need to factor this expression}[/tex] [tex]\textbf{by applying the sum of two cubes rule:}[/tex]
[tex]\Longrightarrow[/tex] [tex]A^{3} +B^{3} =(A+B)(A^{2} -AB+B^{2} )[/tex]
Here,
A= a
B= b
So, [tex](a+b)(a^{2} -ab+b^{2} )[/tex]
[tex]\leadsto\leadsto\leadsto\leadsto\leadsto\leadsto\leadsto\leadsto\leadsto\leadsto[/tex]
[tex]\textsl{OAmalOHopeO}[/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.