Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Step-by-step explanation:
[tex]a {}^{3} + b {}^{3} [/tex]
Notice how that for both a and b are raised to an odd power. This means we can factor this by a binomial raised to an odd power.
Let divide this by
[tex]a + b[/tex]
Since that is also a odd power.
[tex]( {a}^{3} + {b}^{3} ) \div (a + b)[/tex]
We get
a quotient of
[tex]( {a}^{2} - ab + {b}^{2} )[/tex]
So our factors are
[tex](a + b)( {a}^{2} - ab + {b}^{2} )[/tex]
Answer:
[tex](a+b)(a^{2} -ab+b^{2} )[/tex]
Step-by-step explanation:
[tex]\textbf{We need to factor this expression}[/tex] [tex]\textbf{by applying the sum of two cubes rule:}[/tex]
[tex]\Longrightarrow[/tex] [tex]A^{3} +B^{3} =(A+B)(A^{2} -AB+B^{2} )[/tex]
Here,
A= a
B= b
So, [tex](a+b)(a^{2} -ab+b^{2} )[/tex]
[tex]\leadsto\leadsto\leadsto\leadsto\leadsto\leadsto\leadsto\leadsto\leadsto\leadsto[/tex]
[tex]\textsl{OAmalOHopeO}[/tex]
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
