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Sagot :
Answer:
x= 439/999
Step-by-step explanation:
let x= 0.439439.... -> eq.1
1000x= 439.439439.... -> eq.2
eq.2-eq.1 => 1000-x= 439.439....-0.439439...
999x= 439
x= 439/999
Answer:
[tex]\frac{29}{66}[/tex]
Step-by-step explanation:
We require 2 equations with the repeating digits 39 placed after the decimal point.
let x = 0.43939... ( multiply both sides by 10 and 1000 )
10x = 4.3939... → (1)
1000x = 439.3939... → (2)
Subtract (1) from (2) eliminating the repeating digits
990x = 435 ( divide both sides by 990 )
x = [tex]\frac{435}{990}[/tex] = [tex]\frac{29}{66}[/tex] ← in simplest form
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