chin160179
Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Help anyone can help me do the question,I will mark brainlest.​

Help Anyone Can Help Me Do The QuestionI Will Mark Brainlest class=

Sagot :

Answer:

Step-by-step explanation:

14.

by pythagoras,s theorem

[tex]x=\sqrt{2^2+2^2} =\sqrt{8} =\sqrt{4 \times 2} =2\sqrt{2} \\y^2=x^2+2^2=(2\sqrt{2} )^2+2^2=8+4=12=4 \times 3\\y=2\sqrt{3}[/tex]

15.

first perpendicular=y(say)

and second perpendicular=z (say)

y²=9²+7²=81+49=130

z²=y²+5²=130+25=155

x²=z²+4²=155+16=171

x=√(171)

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.