thawin2007
Answered

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The eighth term of a linear sequence is 26. The term-to-term rule is 'add 3
Work out the fourth term of the sequence.
Explain the method you used to solve this problem.

Sagot :

  • Common difference=d=3

Let a be first term

[tex]\\ \rm\longmapsto a_8=a+7d[/tex]

[tex]\\ \rm\longmapsto 26=a+7(3)[/tex]

[tex]\\ \rm\longmapsto a=26-21[/tex]

[tex]\\ \rm\longmapsto a=5[/tex]

Now

[tex]\\ \rm\longmapsto a_4=a+3d[/tex]

[tex]\\ \rm\longmapsto a_4=5+3(3)[/tex]

[tex]\\ \rm\longmapsto a_4=5+9[/tex]

[tex]\\ \rm\longmapsto a_4=14[/tex]

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