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4(6a + 2b^2) - 1/3 (27b^2 - 15a)
if a = -2 and b = 3


Sagot :

Answer:

[tex]4(6a + 2b^2) - 1/3 (27b^2 - 15a)[/tex]

a = -2

b = 3

[tex]4\left(6\left(-2\right)+2^2\right)-1/3\left(27\left(3\right)^2-15\left(-2\right)\right)[/tex]

Follow the PEMDAS order of operations:-

  • Parentheses
  • Exponents
  • Multiplication or Division
  • Addition or Subtraction

[tex]4\left(6\left(-2\right)+2^2\right)[/tex]

calculate within Parentheses

[tex]6\left(-2\right)+2^2[/tex]

[tex]2^{2} =4[/tex]

[tex]6(-2)=-12[/tex]

Add:-

[tex]-12+4=-8[/tex]

[tex]4\left(-8\right)-1/3\left(27\left(3\right)^2-15\left(-2\right)\right)[/tex]

calculate within Parentheses:-

[tex]27\left(3\right)^2-15\left(-2\right)[/tex]

[tex](3)^{2} =9[/tex]

[tex]27*9=243[/tex]

[tex]243-15\left(-2\right)[/tex]

[tex]15(-2)=-30[/tex]

[tex]243-\left(-30\right)[/tex]

[tex]=273[/tex]

[tex]4\left(-8\right)-1/3\cdot \:273[/tex]

Multiply:-

[tex]4\left(-8\right)=-32[/tex]

[tex]-32-1/3\cdot \:273[/tex]

[tex]1/3*273=91[/tex]

[tex]=-32-91[/tex]

[tex]=-123[/tex]

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