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ILL MARK BRAINLIEST TO FIRST CORRECT ANSWER
Dave solved a quadratic equation. His work is shown below, with Step 111 missing.
What could Dave have written as the result from Step 111?
\begin{aligned} \dfrac{1}{3}(x+4)^2&=48 \\\\ &&\text{Step }1 \\\\ x+4&=\pm 12&\text{Step }2 \\\\ x=-16&\text{ or }x=8&\text{Step }3 \end{aligned}
3
1
(x+4)
2
x+4
x=−16
=48
=±12
or x=8
Step 1
Step 2
Step 3
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
\left(\dfrac{1}{3}x+\dfrac{4}{3}\right)^2=48(
3
1
x+
3
4
)
2
=48left parenthesis, start fraction, 1, divided by, 3, end fraction, x, plus, start fraction, 4, divided by, 3, end fraction, right parenthesis, squared, equals, 48
(Choice B)
B
\left(\dfrac{1}{3}x\right)^2+\left(\dfrac{4}{3}\right)^2=48(
3
1
x)
2
+(
3
4
)
2
=48left parenthesis, start fraction, 1, divided by, 3, end fraction, x, right parenthesis, squared, plus, left parenthesis, start fraction, 4, divided by, 3, end fraction, right parenthesis, squared, equals, 48
(Choice C)
C
(x+4)^2=144(x+4)
2
=144left parenthesis, x, plus, 4, right parenthesis, squared, equals, 144
(Choice D)
D
(x+4)^2=16(x+4)
2
=16
