Answered

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A line passes through the point (12,-4) and is perpendicular to the line with the equation y=6x +3

Sagot :

s1m1

Answer:

y= -(1/6)x -2

Step-by-step explanation:

We know:

y= mx +b is the general equation of the line

Was given:

y= 6x +3, has the slope m=6

Find the equation of the line

y= -(1/6)x + b, perpendicular lines have their slope negative reciprocal m=-1/6

Find the y-intercept that is b

for point (x=12, y= -4) the equation of our line becomes

-4 = -(1/6)(12) + b, multiply a fraction and a number  (a/b)*c = ab/c

-4 = -12/6 +b, simplify the fraction

-4 = -2 + b , add 2 to both sides

-4+2 = -2+2 +b , solve for b

-2 = b

The equation of the line that passes through the point (12,-4) and is perpendicular to the line with the equation y=6x +3 is :

y= -(1/6)x -2

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