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In this task, you’ll perform a re-randomization simulation to determine whether the difference of the sample means is statistically significant enough to be attributed to the treatment.

Suppose you have 10 green bell peppers of various sizes from plants that have been part of an experimental study. The study involved treating the pepper plants with a nutrient supplement that would produce larger and heavier peppers. To test the supplement, only 5 out of the 10 peppers come from plants that were treated with the supplement. All 10 peppers were of the same variety and grown under similar conditions, other than the treatment applied to 5 of the pepper plants.

Your task is to examine the claim that the nutrient supplement yields larger peppers. You will base your conclusions on the weight data of the peppers. The table shows the weights of the 10 peppers, in ounces. (Note: Do not be concerned with which peppers received the treatment for now.) In this task, you’ll divide the data into two portions several times, take their means, and find the differences of the means. This process will create a set of differences of means that you can analyze to see whether the treatment was successful.

In This Task Youll Perform A Rerandomization Simulation To Determine Whether The Difference Of The Sample Means Is Statistically Significant Enough To Be Attrib class=
In This Task Youll Perform A Rerandomization Simulation To Determine Whether The Difference Of The Sample Means Is Statistically Significant Enough To Be Attrib class=
In This Task Youll Perform A Rerandomization Simulation To Determine Whether The Difference Of The Sample Means Is Statistically Significant Enough To Be Attrib class=
In This Task Youll Perform A Rerandomization Simulation To Determine Whether The Difference Of The Sample Means Is Statistically Significant Enough To Be Attrib class=
In This Task Youll Perform A Rerandomization Simulation To Determine Whether The Difference Of The Sample Means Is Statistically Significant Enough To Be Attrib class=

Sagot :

DALAU

Answer:

Good Luck!

Step-by-step explanation:

View image DALAU

In the first randomization, the mean of A and B will be 12.5 and 11.46 respectively.

How to calculate the mean?

The mean for the first randomization will be:

Mean of A = (13.6 + 12.14 + 15.9 + 11.2 + 3.7) / 5

= 62.5/5

= 12.5

Mean of B = (5.2 + 8.2 + 11.5 + 13.8 + 14.6) / 5

= 57.3/5

= 11.46

For the second randomization, the mean will be:

A = (8.2 + 13.8 + 15.9 + 9.2 + 9.7)/5

= 56.8/5

= 11.36

B = (12.1 + 14.6 + 13.6 + 11.2 + 11.5)/5

= 63/5

= 12.6

For the third randomization, the mean will be:

A = (8.2 + 9.7 + 11.5 + 14.6 + 15.9)/5

= 59.9/5

= 11.98

B = (12.1 + 13.8 + 13.6 + 11.2 + 9.2)/5

= 59.9/5

= 11.98

Learn more about mean on:

https://brainly.com/question/1136789

#SPJ2

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