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given that tan x =3/7find cos (90-x) giving you answer in 4 significant figures​

Sagot :

Answer:

[tex]\cos \left(90 ^\circ - x\right) \approx 0.1688[/tex]

Step-by-step explanation:

We are given that:

[tex]\displaystyle \tan x = \frac{3}{7}[/tex]

And we want to find the value of:

[tex]\displaystyle \cos \left(90^\circ - x\right)[/tex]

Recall that by definition, tan(θ) = sin(θ) / cos(θ). Hence:

[tex]\displaystyle \frac{\sin x }{\cos x} = \frac{3}{7}[/tex]

And by definition, sin(θ) = cos(90° - θ). Hence:

[tex]\displaystyle \frac{\cos \left(90^\circ - x\right)}{\cos x} = \frac{3}{7}[/tex]

Multiply:

[tex]\displaystyle \cos \left(90 ^\circ - x\right) = \frac{3}{7} \cos x[/tex]

Find cosine. Recall that tangent is the ratio of the opposite side to the adjacent side. Therefore, the opposite side is 3 and the adjacent side is 7.

Thus, by the Pythagorean Theorem, the hypotenuse will be:

[tex]\displaystyle h = \sqrt{3^2 + 7^2} = \sqrt{58}[/tex]

Cosine is the ratio of the adjacent side to the hypotenuse. Therefore:

[tex]\displaystyle \cos x = \frac{7}{\sqrt{58}}[/tex]

Thus:

[tex]\displaystyle \cos \left(90 ^\circ - x\right) = \frac{3}{7} \left(\frac{3}{\sqrt{58}}\right)[/tex]

Use a calculator. Hence:

[tex]\cos \left(90 ^\circ - x\right) \approx 0.1688[/tex]

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