Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Geometry - Triangle d) In the given figure, BE = EC and CE is the bisector of ZACB. Prove that ZBEC = ZACD. E B D С​

Geometry Triangle D In The Given Figure BE EC And CE Is The Bisector Of ZACB Prove That ZBEC ZACD E B D С class=

Sagot :

Answer:

Let m∠BCE = x

Then m∠ACE = x as well since CE is bisecting ∠ACB.

  • m∠ACD + x + x = 180° ⇒
  • m∠ACD = 180° - 2x

Consider ΔBEC

Since BE = EC, the opposite angles are congruent:

  • ∠BCE ≅ ∠CBE

Then:

  • m∠CBE = m∠BCE = x

Find the angle BEC:

  • m∠BEC = 180° - (x + x) = 180° - 2x

Comparing the above we see that:

  • m∠BEC = m∠ACD
  • proved

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.