Answered

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A rectangle has a length of 38 meters less than 8 times its width. If the area of the rectangle is 4050 square meters, find the length of the rectangle.

Sagot :

Let

  • width be x
  • Length=8x-38
  • Area=4050m^2

We know

[tex]\boxed{\sf Area =Length\times Width}[/tex]

[tex]\\ \sf\longmapsto x(8x-38)=4050[/tex]

[tex]\\ \sf\longmapsto 8x^2-38x=4050[/tex]

[tex]\\ \sf\longmapsto 8x^2-38x-4050=0[/tex]

  • By solving

[tex]\\ \sf\longmapsto x=\dfrac{81}{4}\:or\:x=25[/tex]

  • Take x as 25

[tex]\\ \sf\longmapsto Length=8x-38=8(25)-38=200-38=162m[/tex]

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