Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

A rectangle has a length of 38 meters less than 8 times its width. If the area of the rectangle is 4050 square meters, find the length of the rectangle.

Sagot :

Let

  • width be x
  • Length=8x-38
  • Area=4050m^2

We know

[tex]\boxed{\sf Area =Length\times Width}[/tex]

[tex]\\ \sf\longmapsto x(8x-38)=4050[/tex]

[tex]\\ \sf\longmapsto 8x^2-38x=4050[/tex]

[tex]\\ \sf\longmapsto 8x^2-38x-4050=0[/tex]

  • By solving

[tex]\\ \sf\longmapsto x=\dfrac{81}{4}\:or\:x=25[/tex]

  • Take x as 25

[tex]\\ \sf\longmapsto Length=8x-38=8(25)-38=200-38=162m[/tex]

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.