pgonzales15
Answered

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Help please!!! thx...

Help Please Thx class=

Sagot :

[tex]\\ \sf\longmapsto cos\theta=\dfrac{3}{\sqrt{13}}[/tex]

We know

[tex]\boxed{\sf sin^2\theta=1-cos^2\theta}[/tex]

[tex]\\ \sf\longmapsto \sin( \theta) = \sqrt{1 - { \cos}^{2} \theta } \\ \\ \sf\longmapsto \sqrt{1 - {( \frac{3}{ \sqrt{13} }) }^{2} } \\ \\ \sf\longmapsto \sqrt{1- \frac{ {3}^{2} }{ {( \sqrt{13)} }^{2} } } \\ \\ \sf\longmapsto \sqrt{1 - \frac{9}{13} } \\ \\ \sf\longmapsto \sqrt{\frac{13 - 9}{13} } \\ \\ \sf\longmapsto \sqrt{ \frac{4}{13} } \\ \\ \sf\longmapsto \frac{2}{ \sqrt{13} } [/tex]

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