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I bet no one can solve this


If an electric current of 8.50 A flows for 3.75 hours through an electrolytic cell containing copper-sulfate (CuSO4) solution, then how much copper is deposited on the cathode (the negative electrode) of the cell? (Copper ions carry two units of positive elementary charge, and the atomic mass of copper is 63.5 g/mol.)​

Sagot :

the answer is 89.4 g/mol cuz the two units carry positives so that means 8.50 flows for 2 more hours than usual.
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