Step-by-step explanation:
Let find the distance of the diameter. using distance formula.
[tex](3 + 1) {}^{2} + ( - 2 + 6) {}^{2} = \sqrt{8} [/tex]
The diameter is sqr root of 8 units.
A circle equation is
[tex] {x}^{2} + {y}^{2} = {r}^{2} [/tex]
where r is the radius. The radius is half the diameter so
[tex]r = \frac{ \sqrt{8} }{2} = \frac{ \sqrt{8} }{ \sqrt{4} } = \sqrt{2} [/tex]
[tex] {r}^{2} = { \sqrt{2} }^{2} = 2[/tex]
So our radius is 2.
Now we need to find the midpoint or Center of the diameter.
[tex] \frac{ - 6 - 2}{2} = - 4[/tex]
[tex] \frac{3 - 1}{2} = 1[/tex]
So the center of the circle is (-4,1). So our equation of the Circle us
[tex](x + 4) {}^{2} + (y - 1) {}^{2} = ( \sqrt{2} ) {}^{2} [/tex]
