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Given that log 2 = 0.3010 and log 7 = 0.8451, find the following (a) log 49 (b) log 560​

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Answer:

Log 49= 1.6902

Log 560= 1.7481

Step-by-step explanation:

log49= log7×7

From the rules of logarithms, we have that

log a×b= log a + log b

So log49= log7×7= log7 + log7

= 0.8451 + 0.8451 = 1.6902

Log 560 = log7×8 = log7 + log8

log8= log2^3 = 3log2

log8= 3×0.3010 =0.930

log 560= 0.8451 + 0.930 = 1.7481

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