Bikram2468
Answered

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A car of 1000 kg starts to move from rest and travels a distance of 150 m in 10 second. How much force is needed?​

Sagot :

  • Initial velocity=u=0m/s
  • Distance=s=150m
  • Time=t=10s
  • Acceleration=a

Using second equation of kinematics

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\longmapsto 150=0(10)+\dfrac{1}{2}a(10)^2[/tex]

[tex]\\ \sf\longmapsto 150=\dfrac{1}{2}\times 100a[/tex]

[tex]\\ \sf\longmapsto 50a=150[/tex]

[tex]\\ \sf\longmapsto a=\dfrac{150}{50}[/tex]

[tex]\\ \sf\longmapsto a=3m/s^2[/tex]

  • Mass=m=1000kg
  • Force=F

Using newtons second law

[tex]\\ \sf\longmapsto F=ma[/tex]

[tex]\\ \sf\longmapsto F=1000(3)[/tex]

[tex]\\ \sf\longmapsto F=3000N[/tex]

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