Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
First
[tex]\\ \sf\longmapsto BD^2=AD\times DC[/tex]
[tex]\\ \sf\longmapsto BD^2=18^2+7^2[/tex]
[tex]\\ \sf\longmapsto BD^2=324+49[/tex]
[tex]\\ \sf\longmapsto BD^2=363[/tex]
[tex]\\ \sf\longmapsto BD=\sqrt{363}[/tex]
[tex]\\ \sf\longmapsto BD=19.2[/tex]
Now
Using Pythagorean theorem
[tex]\\ \sf\longmapsto BD^2+CD^2=m^2[/tex]
[tex]\\ \sf\longmapsto m^2=7^2+19.2^2[/tex]
[tex]\\ \sf\longmapsto m^2=49+363[/tex]
[tex]\\ \sf\longmapsto m^2=412[/tex]
[tex]\\ \sf\longmapsto m=\sqrt{412}[/tex]
[tex]\\ \sf\longmapsto m=20.3[/tex]
Nearest value in options is 18
Hence option a is correct
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.