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Sagot :
Answer:
see explanation
Step-by-step explanation:
If 2 angles and the included side of one triangle are congruent to 2 angles and the included side of another triangle, then the triangles are congruent.
NQ is an angle bisector then ∠ MNQ = ∠ PNQ
∠ M = ∠ N , so the triangle is isosceles with 2 equal legs, then
MN = PN
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∠ MNQ = ∠ PNQ
MN = PN ( included sides between the 2 angles )
∠ M = ∠ N
Δ MNQ ≅ Δ PNQ by the ASA postulate
Answer:
Step-by-step explanation:
In Δ MNP,
∠NMQ ≅ ∠NPQ
⇒ NM = NP - ------> (I) {Sides opposite to equal angles are equal}
In ΔMNQ & ΔPNQ,
∠MNQ ≅ ∠PNQ {NQ is angle bisector}
NM = NP {from (I)}
∠NMQ ≅ ∠NPQ {Given}
ΔMNQ ≅ ΔPNQ - Angle Side Angle {ASA congruent}
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