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pleaseee help help

The sign at the tee off area for a hole on a golf course indicates the hole is 340
yards from the tee. The golfers drive went to the right. The caddie paced the
drive to be 230 yards. The yardage markers indicate the ball is still 175 yards
from the hole. Determine the angle the golfer went off line from the tee when they
drove the ball.


Sagot :

The angle the golfer went off line from the tee when they  drove the ball

is [tex]\phi=28.2 \textdegree[/tex] because the cosine rule has been applied to calculate the angle

From the question we are told that:

Distance of hole from tee [tex]d_h=340yards[/tex]

Distance to the right [tex]d_r=230yards[/tex]

Ball distance from hole [tex]d_b=175 yard[/tex]

Given that the three points form a triangle x,y,z respectively

Where

[tex]d_h=xz[/tex]

[tex]d_r=xy[/tex]

[tex]d_b=yz[/tex]

Using Cosine Rule

[tex]yz^2=xy^2+xz^2-2(xy)(xz)cos\phi[/tex]

Therefore

[tex]cos\phi=\frac{yz^2}{xy^2+xz^2-2(xy)(xz)}[/tex]

[tex]cos\phi=\frac{(175)^2}{230^2+340^2-2(230)(340)}[/tex]

[tex]cos\phi=0.88[/tex]

[tex]\phi=28.2 \textdegree[/tex]

In conclusion the angle the golfer went off line from the tee when they

drove the ball is mathematically deducted and give as

[tex]\phi=28.2 \textdegree[/tex]

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