Answered

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question 8b , thanks

Question 8b Thanks class=

Sagot :

devishri1977

Answer:

Step-by-step explanation:

[tex]a = \frac{2b+1}{3b-1}[/tex]

b = 2/3

[tex]2b + 1 = 2*\frac{2}{3}+1\\\\=\frac{4}{3}+1\\\\=\frac{4}{3}+\frac{3}{3}\\\\=\frac{7}{3}\\\\3b-1 = 3*\frac{2}{3}-1\\\\=2- 1 = 1\\\\\\[/tex]

[tex]a = \frac{2b+1}{3b-1}\\\\a=\frac{\frac{7}{3}}{1}\\\\=\frac{7}{3}\\\\[/tex]

a = 7/3

b)

[tex]\frac{2b+1}{3b-1}=a\\\\[/tex]

Cross multiply,

2b + 1 = a*(3b - 1)

2b + 1 = a*3b - 3*a

2b + 1 = 3ab- 3a

2b = 3ab - 3a - 1

2b - 3ab = -3a  - 1

b(2 - 3a) = -3a - 1

[tex]b =\frac{-3a - 1}{2 - 3a}[/tex]

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