madisonhemmo7
Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Another distribution problem. Can someone solve?

Another Distribution Problem Can Someone Solve class=

Sagot :

caylus

Answer:

Hello,

Step-by-step explanation:

[tex]P(3000<x<4000)\\\\=P(\dfrac{3000-3262}{1100} \leq z\leq \dfrac{4000-3262}{1100})\\\\=P(z\leq 0,6709)-(1-P(z\leq 3524) \leq z))\\\\=0.7515-0.5941\\\\=0.1574\\[/tex]

My table have 4 digits but i have made a linear interpolation .

madethisfortwitch1

Answer:

-.238, .67, .7486, .4052, .3434

Step-by-step explanation:

standardize them both

(3000-3262)/1100= -.238 which rounds to -.24 which has a probability of .4052

(4000-3262)/1100= .67 which has a probability of .7486

subtract them

.7486-.4052=.3434

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.