Answered

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Please help, need to find f^-1 (x)

Please Help Need To Find F1 X class=

Sagot :

LammettHash

The inverse function [tex]f^{-1}(x)[/tex] is such that

[tex]f\left(f^{-1}(x)\right) = x[/tex]

Plugging [tex]f^{-1}(x)[/tex] into [tex]f(x)[/tex] gives us

[tex]f\left(f^{-1}(x)\right) = \dfrac{3f^{-1}(x) + 3}{5f^{-1}(x) + 6} = x[/tex]

Solve for [tex]f^{-1}(x)[/tex] :

[tex]\dfrac{3f^{-1}(x) + 3}{5f^{-1}(x) + 6} = x \\\\ 3f^{-1}(x)+3=x\left(5f^{-1}(x)+6\right) \\\\ 3f^{-1}(x) + 3 = 5x f^{-1}(x)+6x \\\\ 5xf^{-1}(x)-3f^{-1}(x) = 3 - 6x \\\\ (5x-3)f^{-1}(x)=3-6x \\\\ \boxed{f^{-1}(x)=\dfrac{3-6x}{5x-3}}[/tex]

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