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If triangle ABC has the following measurements, what is the measure of angle B? a=5 b=7 c=10

Sagot :

yegagurung2007

Answer: about 40.54°

Step by step explanation:

7^2 =  5^2 + 10^2  - 2(5)(10)cos(B)

cos(B)  = (7^2 - 5^2 - 10^2) / (-2(5)(10) )

B = cos-1 [ (7^2 - 5^2 - 10^2) / (-2(5)(10) ]  =  cos-1 (.76) = about 40.54°

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