malolomom
Answered

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How many real solutions does this system of equations have? x2 +3 = y
3х — у+1 = 0

How Many Real Solutions Does This System Of Equations Have X2 3 Y 3х У1 0 class=

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Answer:

Step-by-step explanation:

y = x²+3

y = 3x+1

x² + 3 = 3x +1

x² - 3x + 2 = 0

(x-2)(x-1) = 0

x = 2, 1

Two solutions

(2,7) and (1,4)

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