Answered

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HELP PLEASE!

The length of a rectangle is 2V5. The width of the same rectangle is 5V5. Find the perimeter and area of the rectangle.

HELP PLEASE The Length Of A Rectangle Is 2V5 The Width Of The Same Rectangle Is 5V5 Find The Perimeter And Area Of The Rectangle class=

Sagot :

Answers:

[tex]\text{Perimeter} = 14\sqrt{5}\\\\\text{Area} = 50\\\\[/tex]

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Work Shown:

[tex]L = 2\sqrt{5} = \text{length}[/tex]

[tex]W = 5\sqrt{5} = \text{width}[/tex]

P = perimeter

[tex]P = 2*(L+W)\\\\P = 2*(2\sqrt{5}+5\sqrt{5})\\\\P = 2*(7\sqrt{5})\\\\P = 14\sqrt{5}\\\\[/tex]

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A = area

[tex]A = L*W\\\\A = (2\sqrt{5})*(5\sqrt{5})\\\\A = (2*5)(\sqrt{5}*\sqrt{5})\\\\A = 10\sqrt{5*5}\\\\A = 10\sqrt{25}\\\\A = 10*5\\\\A = 50\\\\[/tex]

junistaken1
Area=5rad5 times 2rad5 equals 50 Bc rad 5 times rad 5 is rad 25 or 5 and 2 timers 5 is ten so now it is 5 times 10=50
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