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A circle is centered at (7, 8) and has a radius of 11. Which of the following is the equation for this circle? (x − 7)2 + (y − 8)2 = 121 (x − 7)2 + (y − 8)2 = 11 (x + 7)2 + (y + 8)2 = 121 (x + 7)2 + (y + 8)2 = 11

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Answer:

(x − 7)2 + (y − 8)2 = 11

Step-by-step explanation:

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The equation of the circle with center at (7, 8) and radius of 11 is

(x - 7)²  +  (y - 8)²  =121

The equation of a circle with center at (a, b) and radius of r is:

(x - a)²  +  (y - b)²  =  r²

The center of the circle, (a, b)  =  (7, 8)

That is, a = 7, b = 8

The radius, r = 11

Substitute a = 7, b = 8, and r = 11 into the equation (x - a)²  +  (y - b)²  =  r²:

(x - 7)²  +  (y - 8)²  =  11²

(x - 7)²  +  (y - 8)²  = 121

Therefore, the equation of the circle with center at (7, 8) and radius of 11 is

(x - 7)²  +  (y - 8)²  =121

Learn more here: https://brainly.com/question/23226948

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