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Sagot :
Answer:
The equation x
The equation x 2
The equation x 2 +xy+xz+yz can be factorised as follows:
The equation x 2 +xy+xz+yz can be factorised as follows:x
The equation x 2 +xy+xz+yz can be factorised as follows:x 2
The equation x 2 +xy+xz+yz can be factorised as follows:x 2 +xy+xz+yz=(x
The equation x 2 +xy+xz+yz can be factorised as follows:x 2 +xy+xz+yz=(x 2
The equation x 2 +xy+xz+yz can be factorised as follows:x 2 +xy+xz+yz=(x 2 +xy)+(xz+yz)=x(x+y)+z(x+y)=(x+z)(x+y)
The equation x 2 +xy+xz+yz can be factorised as follows:x 2 +xy+xz+yz=(x 2 +xy)+(xz+yz)=x(x+y)+z(x+y)=(x+z)(x+y)Hence, x
The equation x 2 +xy+xz+yz can be factorised as follows:x 2 +xy+xz+yz=(x 2 +xy)+(xz+yz)=x(x+y)+z(x+y)=(x+z)(x+y)Hence, x 2
The equation x 2 +xy+xz+yz can be factorised as follows:x 2 +xy+xz+yz=(x 2 +xy)+(xz+yz)=x(x+y)+z(x+y)=(x+z)(x+y)Hence, x 2 +xy+xz+yz=(x+z)(x+y)
Answer:
= (y-1) (xy-z)
Step-by-step explanation:
First we expand them -
= xy^2 - xy - yz - z
= xy(y-1)-z(y-1)
= (y-1) (xy-z)
Hope this helped
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