Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

The length of a rectangle is 2 cm less than twice the width. The area of the rectangle is 112 cm2. Find the length and width of the rectangle.

Sagot :

Let breadth be x

  • Length=2x-2

We know

[tex]\boxed{\sf Area=Length\times Breadth}[/tex]

[tex]\\ \sf\longmapsto 112=x(2x-2)[/tex]

[tex]\\ \sf\longmapsto 2x^2-2x-112=0[/tex]

[tex]\\ \sf\longmapsto x=-7\:or\:x=8[/tex]

  • Ignore negative value

Now

[tex]\\ \sf\longmapsto Length=2x-2=2(8)-2=16-2=14[/tex]

[tex]\\ \sf\longmapsto Breadth=8[/tex]

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.