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The length of a rectangle is 2 cm less than twice the width. The area of the rectangle is 112 cm2. Find the length and width of the rectangle.

Sagot :

Let breadth be x

  • Length=2x-2

We know

[tex]\boxed{\sf Area=Length\times Breadth}[/tex]

[tex]\\ \sf\longmapsto 112=x(2x-2)[/tex]

[tex]\\ \sf\longmapsto 2x^2-2x-112=0[/tex]

[tex]\\ \sf\longmapsto x=-7\:or\:x=8[/tex]

  • Ignore negative value

Now

[tex]\\ \sf\longmapsto Length=2x-2=2(8)-2=16-2=14[/tex]

[tex]\\ \sf\longmapsto Breadth=8[/tex]