Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

The length of a rectangle is 2 cm less than twice the width. The area of the rectangle is 112 cm2. Find the length and width of the rectangle.

Sagot :

Let breadth be x

  • Length=2x-2

We know

[tex]\boxed{\sf Area=Length\times Breadth}[/tex]

[tex]\\ \sf\longmapsto 112=x(2x-2)[/tex]

[tex]\\ \sf\longmapsto 2x^2-2x-112=0[/tex]

[tex]\\ \sf\longmapsto x=-7\:or\:x=8[/tex]

  • Ignore negative value

Now

[tex]\\ \sf\longmapsto Length=2x-2=2(8)-2=16-2=14[/tex]

[tex]\\ \sf\longmapsto Breadth=8[/tex]

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.