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Two points, A and B, are on opposite sides of a building. A surveyor chooses a third point, C, 80 yd from B and 104 yd from A, with angle ACB
measuring 51.2º. How far apart are A and B (to the nearest yard)?


HURRYYY GIVING 20 POINTS!!


Two Points A And B Are On Opposite Sides Of A Building A Surveyor Chooses A Third Point C 80 Yd From B And 104 Yd From A With Angle ACB Measuring 512º How Far A class=

Sagot :

Answer:

Step-by-step explanation:

View image xenia168

The law of cosine helps us to know the third side of a triangle when two sides of the triangle are already known the angle opposite to the third side is given. The distance between A and B is 85.6 yds.

What is the Law of Cosine?

The law of cosine helps us to know the third side of a triangle when two sides of the triangle are already known the angle opposite to the third side is given. It is given by the formula,

[tex]c =\sqrt{a^2 + b^2 -2ab\cdot Cos\theta}[/tex]

where

c is the third side of the triangle

a and b are the other two sides of the triangle,

and θ is the angle opposite to the third side, therefore, opposite to side c.

The three points A, B, and C will form a triangle. Therefore, using the law of cosine the measure of the third side AB can be written as,

[tex]AB =\sqrt{(AC)^2 + (BC)^2 -2(AC)(BC)\cdot \cos(51.2^o)}\\\\AB =\sqrt{(80)^2 + (104)^2 -2(80)(104)\cdot \cos(51.2^o)}\\\\AB = \sqrt{6400+10816-16640\cos51.2^o}\\\\AB = \sqrt{7328.4}\\\\AB=85.6\rm\ yd[/tex]

Hence, the distance between A and B is 85.6 yds.

Learn more about the Law of Cosine:

https://brainly.com/question/17289163

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