Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Help very confusing to me???!

Help Very Confusing To Me class=

Sagot :

Answer:

Heyy mate... here's ur ans ;)

they asked us to apply pythagarus theorem becoz that theorem proves

that it is rectangle so lets get started

( p - perpendicular / b - base / h - hypotenuse )

a) =>

B = 8.1 m

P = 6.3 m

H = 10.15m

Now applying thm => H^2=p^2+b^2

(8.1)^2 + (6.3)^2 = (10.15)^2

65.61 + 39.69 = 103.02

so now LHS = 105.3 and RHS = 103.02 hence

LHS not equal to RHS

so is not rectangle

b) =>

B = 14.4

P = 5.2

H = 15.31

Now applying thm => H^2=p^2+b^2

(5.2)^2 + (14.4)^2 = (15.31)^2

27.04 + 207.36 = 234.39

LHS = 234.4 and RHS = 234.39

just taking approximation rhs is 234.4

hence

LHS = RHS

so it is a rectangle

please mark it brainliest <3

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.