Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
We have to solve this question using the stoichiometry of the reaction using number of moles:
The equation of the reaction is;
[tex]2 C12H26(l) + 37 O2(g) -----> 24 CO2(g) + 26 H2O(l) + 15,026 kJ[/tex]
According to the question;
Number of moles of CO2 released = 21.3 g/44 g/mol = 0.48 moles
From the stoichiometry of the reaction:
Since;
24 moles of CO2 released 15,026 KJ
0.48 moles of CO2 will release 0.48 * 15,026/24
= 301 KJ of heat.
https://brainly.com/question/6901180
Answer:
2 C12H26(l) + 37 O2(g) ----- > 24 CO2(g) + 26 H2O(l) + 15,026 kJ2C12H26(l)+37O2(g)−−−−−>24CO2(g)+26H2O(l)+15,026kJ
According to the question;
Number of moles of CO2 released = 21.3 g/44 g/mol = 0.48 moles
Since;
24 moles of CO2 released 15,026 KJ
0.48 moles of CO2 will release 0.48 * 15,026/24
= 301 KJ of heat.
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.